Question

Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M solution? *

Answer 1

Answer: The volume of stock solution needed is 90 mL

Step-by-step explanation:

To calculate the molarity of the diluted solution, we use the equation:

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the molarity and volume of the stock sulfuric acid solution

`M_2\text{ and }V_2` are the molarity and volume of diluted sulfuric acid solution

We are given:

`M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL`

Putting values in above equation, we get:

`6.0* V_1=1.2* 450\\\\V_1=(1.2* 450)/(6.0)=90mL`

Hence, the volume of stock solution needed is 90 mL