Answer:
Therefore,
![(-2)^(3)=-8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lj7l6sj0ev8e6jc95y486z3g9issjdm6nc.png)
Explanation:
Simplify
-2^3
![(-2)^(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1z24zmd9iuxumcrwe0wskmtt915wjr6g1n.png)
It is read as negative 2 raised to the power three,
also it is the cube of negative 2
we know that
given as
![a^(3)=a* a* a](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9dlii5e6ct93uwdt4lpkeamuet92ra3byq.png)
so for negative a i.e -a
![(-a)^(3)=-a* -a* -a](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bhdf6twmris0oob1n3c6hqar98wwnfam0x.png)
substituting a = 2 we get
![(-2)^(3)=-2* -2* -2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6mx3j4m29ipvab0aaws0p5g6w566qtg6fm.png)
negative sign multiplied by odd number of times then the sign remains negative.
Therefore,
![(-2)^(3)=-8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lj7l6sj0ev8e6jc95y486z3g9issjdm6nc.png)