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the volume of an iron sphere is 3.00cm cubed after being heated from 20.0c to 600.0 c what was the initial volume of the iron sphere at 20.0c

2 Answers

4 votes

Answer: 1cm3

Explanation:

V1 =?

V2 = 3cm3

T1 = 20°C = 20 + 273 = 293K

T2 = 600°C = 600 + 273 = 873K

V1 /T1 = V2 /T2

V1 / 293 = 3 / 873

V1 = 293 x ( 3 / 873)

V1 = 1 cm3

User Mohammed Zayan
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4.9k points
3 votes

Answer:

V = 2.94cm³

The initial volume at 20°C is 2.94cm³

Step-by-step explanation:

As the temperature of the iron sphere increases the volume of the sphere also increase.

Using the equation for volumetric expansion:

∆V = VαΔT

where ;

V is the initial volume

α is the volumetric expansion coefficient

∆V is the change in Volume

∆T is the change in temperature

After Expansion the final volume can be written as:

Vf = V + ∆V

Vf = V + VαΔT

Vf = V(1 + αΔT)

making V the subject of formula;

V = Vf/(1+αΔT) .....1

Given:

Vf = 3.00cm³

ΔT= 600-20 = 580

And from the test book.

α = 35.5 × 10⁻⁶K⁻¹

Substituting the values into eqn 1

V = 3.00/(1+580× 35.5×10^-6)

V = 3.00/(1+0.021) = 3.00/1.021

V = 2.94cm³

The initial volume at 20°C is 2.94cm³

User Harshavardhan
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5.1k points