Answer:
The main solution to this problem is to note that under equilibrium conditions, the rate at which heat is transferred into the metal plate from the sun by radiation must be equal to the rate at which heat is lost from the plate to the surrounding air by convection.
Step-by-step explanation:
Therefore, qᵃ = qᵇΔT
where
a = Radiation energy source
b = Convection energy source
ΔT = Tp - Ta = Temperature change between the plate and the air under equilibrium condition
Given,
qᵃ = 700 W/m2
qᵇ = 10 W/m2K - 100 W/m2K
Hence, for qᵇ = 10 W/m2K,
ΔT = qᵃ / qᵇ
ΔT = 700/10 = 70K
Similarly, for qᵇ = 100 W/m2K
ΔT = 700/100 = 7K
The temperature change of the plate under equilibrium conditions range from 7K to 70K.