Question

A Ping-Pong ball has a diameter of 2.55 cm and average density of 0.116 g/cm3 . What force would be required to hold it completely submerged under water?

Answer 1

F = 0.075 N

Step-by-step explanation:

given,

diameter of ping pong ball = 2.55 cm

average density of the ball = 0.116 g/cm³

Force require to hold the ball completely submerged= ?

Volume of the ball

`V = (4)/(3) \pi r^3`

`V = (4)/(3) \pi ((2.55)/(2))^3`

V = 8.63 cm³

density of water = 1 g/cm³

force required to keep the ball submerged is equal to

`F = \rho_w V_w g - \rho_b V g`

`F = 1* 8.63* g - 0.116 * 8.63 * g`

F = 7.63 x 9.8 x 10⁻³

F = 0.075 N

Force required to keep the ball inside the water is equal to 0.075 N