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The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one of these spheres to make it electrically neutral?

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Answer:


1.873* 10^(13) electrons should be added to one of these spheres to make it electrically neutral.

Step-by-step explanation:

Total charge on each sphere = +3.0 μC =
3* 10^(-6) C


1 \mu C=10^(-6) C

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q= -3.0 μC =
-3* 10^(-6) C

Number of electrons = n

Charge on a single electron, e =
-1.602* 10^(-19) C

Q = n × e


-3* 10^(-6) C=n* (-1.602* 10^(-19) C)


n=(-3* 10^(-6) C)/(-1.602* 10^(-19) C)=1.873* 10^(13)


1.873* 10^(13) electrons should be added to one of these spheres to make it electrically neutral.

User Ian Langmore
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