Question

Write an equation of the line that is perpendicular to y=1/2x-3 and goes through the point (1,3)

Answer 1

y = -2x + 5

Explanation:

y=
`(1)/(2)x`-3

Slope of this line m₁ = 1/2

Slope of the line perpendicular to this line = m₂

m₁ *m₂ = -1

m₂ = -1 *2/1 = -2

Slope = -2; (1,3)

y- y₁ = m(x-x₁)

y - 3 = -2(x - 1)

y - 3 = -2x + 2

y = -2x +2 +3

y = -2x + 5