Question

A 0.1 kg object moving initially with a velocity of +0.2 m/s makes an elastic head-on collision with a 0.15 kg object initially at rest. What is the final velocity of the 0.1 kg object after the collision?

Answer 1

v₁=0.2 ms

Step-by-step explanation:

Given that

m₁ = 0.1 kg

u₁ = 0.2 m/s

m₂ = 0.15 kg

u₂ = 0 m/s

Lets take the final speed of the 0.1 kg ball = v₁

Lets take the final speed of the 0.15 kg ball = v₂

Given that collision is elastic that is why e = 1

`e=(v_2-v_1)/(u_1-u_2)`

`1=(v_2-v_1)/(u_1-u_2)`

u₁ - u₂ = v₁ - v₂

0.2 - 0 = v₁ - v₂

v₁ - v₂ = 0.2 ------------1

If there is no any external force on the system then the total linear momentum of the system will be conserve.

m₁u₁ + m₂ u₂ =m₂ v₂ +m₁v₁

0.2 x 0.1 + 0 = 0.15 v₂ + 0.1 v₁

0.02 = 0.1 v₁ + 0.15 v₂

2 = 10 v₁ + 15 v₂ ----------------2

By using equation 1 and 2

We can say that

v₁=0.2 ms

v₂ =0 m/s