Question

Suppose you have a 100-gram sample of each of the following compounds. Which sample contains the largest number of moles of compound?chromium(III) chlorideammoniamagnesium chloridephosphoric acidpotassium chloridenitrogen trioxidemethanepropanelithium chlorate

Answer 1

Step-by-step explanation:

In order to calculate the number of moles of a compound, we will find it out as follows.

No. of moles of chromium(III) chloride =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(158.36)`

= 0.63 moles

No. of moles of
`NH_(3)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(17)`

= 5.88 moles

No. of moles of
`MgCl_(2)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(95)`

= 1.05 moles

No. of moles of
`H_(3)PO_(4)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(98)`

= 1.02 moles

No. of moles of KCl =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(74.5)`

= 1.34 moles

No. of moles of
`N_(2)O_(3)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(76)`

= 1.31 moles

No. of moles of
`CH_(4)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(16)`

= 6.25 moles

No. of moles of
`C_(3)H_(8)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(44)`

= 2.27 moles

No. of moles of
`LiClO_(3)` =
`\frac{mass}{\text{molar mass}}`

=
`(100)/(90.39)`

= 1.11 moles

Therefore, we can conclude that out of the given options
`CH_(4)` contains the largest number of moles of compound.