Question

NEED HELP ON THIS ASAP

Answer 1

Option 3 is correct.

`V_(s)=23976\ cubic\ feet`

Explanation:

Given:

The dimension of the large box.

Length = 40 ft,width = 24, height = 18

The dimension of the smaller box.

Box 1 ⇒ Length = 30 ft, width = 18 ft, height = 6 ft

Box 2 ⇒ Length = 30 ft, width = 12 ft height = 6 ft

Box 3 ⇒ Length = 18 ft, width = 12 ft, height = 6 ft

We need to find the volume of the solid.

Solution:

First we find the volume of the all boxes by using below formula.

`Volume = Length* width* height`

Volume of the large box.

`Volume = Length* width* height`

So, the volume of the large box.

`V_(lb) = 40* 24* 18`

`V_(lb) = 17280\ cubic\ feet`

Volume of the smaller box(box 1).

`Volume = Length* width* height`

So, the volume of the large box.

`V_(b1) = 30* 18* 6`

`V_(b1) = 3240\ cubic\ feet`

Volume of the smaller box(box 2).

`Volume = Length* width* height`

So, the volume of the large box.

`V_(b2) = 30* 12* 6`

`V_(b2) = 2160\ cubic\ feet`

Volume of the smaller box(box 3).

`Volume = Length* width* height`

So, the volume of the large box.

`V_(b3)= 18* 12* 6`

`V_(b3)= 1296\ cubic\ feet`

We know that the volume of the solid is equal to sum of the all boxes.

Volume of the solid

`V_(s) = V_(lb)+V_(b1)+V_(b2)+V_(b3)`

`V_(s) = 17280+3240+2160+1296`

`V_(s)=23976\ cubic\ feet`

Therefore, the volume of the solid
`V_(s)=23976\ cubic\ feet`