Question

Please Help ME!!!!!!!!!!!!!!

Answer 1

The empirical formula of this question is :

C.

`C_(5)H_(7)`

Step-by-step explanation:

The empirical formula is the simplest whole number ratio of elements in the chemical formula of the molecule.

It is calculated using:

`Empirical\ formula=(Molecular\ formula)/(n)`

n = The common factor

The Molecular formula represents the exact composition of the elements in the compound.

For example :

Molecular formula : C4H8O2

Find the common factor n ?

here , 2 is common factor(which is divisible by 4 ,8,2)

`Empirical\ formula=(Molecular\ formula)/(2)`

divide each element by 2

`Empirical\ formula=C_(2)H_(4)O_(1)`

generally 1 is not written

C2H4O is the empirical formula

In this question , the molecular formula C40H56

n = common factor = 8(It is divisible by 40 , 56 )

`Empirical\ formula=(Molecular\ formula)/(8)`

`Empirical\ formula=C_(5)H_(7)`

So, correct option is C