Question

A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured by an observer on the ground, not by the bird). The bird opens its mouth wide and enjoys a nice lunch.

What is the bird's speed immediately after swallowing?

Answer 1

The bird's speed immediately after swallowing is 4.98 m/s.

Step-by-step explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

`m_(1)v_(1)+m_(2)v_(2)=(m_(1)+m_(2))v_(3)`

Put the value into the formula

`0.290*6.2+0.009*(-34)=(0.290+0.009)* v_(3)`

`v_(3)=(0.290*6.2-0.009*34)/((0.290+0.009))`

`v_(3)=4.98\ m/s`

Hence, The bird's speed immediately after swallowing is 4.98 m/s.