Question

A projectile falls beneath the straight-line path it would follow if there were no gravity. How many meters does it fall below this line if it has been traveling for 1 sec? 2 sec?

Answer 1

Step-by-step explanation:

In order to solve the problem we will use the following newton's equation of motion.

`S = ut+(1)/(2) gt^(2)`

S = ?

u (initial velocity) = 0

g = 9.8
`m/s^(2)`

For t = 1 s

`s = 0+(1)/(2) (9.8)(1^(2))`

s = 4.9 m = 5m.

For t = 2 s

`S = 0+(1)/(2)(9.8)(2^(2))`

s = 19.6 m = 20m