Question

A sample of iron metal absorbs 4.56 J of heat, upon which the temperature of the sample increased from 29 °C to 36 °C. Which of the following is the mass of the sample? Cs of iron is 0.46 J/g °C.

a) 1.22 g
b) 1.42 g
c) 4.12 g
d) 3.22 g

Answer 1

b) 1.42 g

Step-by-step explanation:

Data Given:

Amount of Heat = 4.56 J

initial temperature = 29 °C

Final temperature = 36 °C

Cs of iron = 0.46 J/g °C

mass of sample = ?

Solution:

Formula used

Q = Cs.m.ΔT

rearrange the above equation to calculate the mass of iron sample

m = Q / Cs.ΔT .... . . . . . (1)

Where:

Q = amount of heat

Cs = specific heat of iron = 0.46 J/g °C

m = mass

ΔT = (t2 - t1) = Change in temperature

First we have to find ΔT

ΔT = (t2 - t1)

ΔT = (36 °C - 29°C )

ΔT = 7 °C

Put values in above equation 1

m = 4.56 J / 0.46 (J/g °C) x 7 °C

m =4.56 J / 3.22 (J/g)

m = 1.42 g

So option b is correct = 1.42 g