Answer:
Explanation:
A school's rectangular athletic field has a length of 125 yards and a width of 75 yards. The planning committee has decided to expand both the length and the width of the field by a certain number of yards ... say x. This means that the new length would be 125 + 2x and the new width would be 75 + 2x
Therefore, the new area would be
A(x) = (125 + 2x)(75 + 2x) = 9375 + 250x + 150x + 4x^2
A(x) = 4x^2 + 400x + 9375