Question

If a balloon contains 3.00 L of air that has a pressure of 36.74 psi, what is the gas volume (the volume of the balloon) once it floats to the surface?

Answer 1

7.5 L

Step-by-step explanation:

At constant temperature and number of moles, Using Boyle's law

`{P_1}* {V_1}={P_2}* {V_2}`

Given ,

V₁ = 3.00 L

V₂ = ?

P₁ = 36.74 psi = 2.5 atm (Conversion factor, 1 psi = 0.068046 atm)

P₂ = 1 atm (Atmospheric pressure as it comes to surface)

Using above equation as:

`{P_1}* {V_1}={P_2}* {V_2}`

`{2.5\ atm}* {3.00\ L}={1\ atm}* {V_2}`

`{V_2}=\frac{{2.5}* {3.00}}{1}\ L`

`{V_2}=7.5\ L`