Question

There are 15 different apples and 10 different pears. How many ways are there for Jack to pick an apple or a pear and then for Jill to pick an apple and a pear?

Answer 1

`15 \cdot 10 (14+9)=3450 ways`

Explanation:

There are 15 different apples and 10 different pears

Jack can pick an apple in 15 ways and then Jill has a chance of picking an apple from 14 apples and pear from 10 pears. So, total of
`15 \cdot 14 \cdot 10` ways

Jack can pick a pear in 10 ways and then Jill has a chance of picking an apple from 15 apples and pear from 9 pears. So total of
`10 \cdot 15 \cdot 9` ways

Number of possible ways =
`(15 \cdot 14 \cdot 10)+(10 \cdot 15 \cdot 9)=15 \cdot 10 (14+9)=3450 ways`