Question

The Grand Canyon is 1800 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of the rock as a function of the time in seconds. How long will it take the rock to hit the canyon floor?

Answer 1

Step-by-step explanation:

Given

height of grand canyon is
`h=1800\ m`

Rock is dropped i.e. initial velocity is zero

`u=0`

Using Equation of motion

`h=ut+(1)/(2)at^2`

h=height

u=initial velocity

a=acceleration

t=time

here a=acceleration due to gravity

`1800=0+(1)/(2)* 9.8* t^2`

`t^2=(2* 1800)/(9.8)`

`t=19.166\ s`