Answer: About 191 students scored between a 60 and an 80.
Explanation:
Given : A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5.
i.e.
and
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let x be the random variable that denotes the test scores.
Then, the probability that the students scored between a 60 and an 80 :
![P(60<x<80)=P((60-70)/(5)<(x-\mu)/(\sigma)<(80-70)/(5))\\\\=P(-2<z<2)\ \ [\because z=(x-\mu)/(\sigma)]\\\\=P(z<2)-P(z<-2)\ \ [\because\ P(z_1<Z<z_2)=P(Z<z_2)-P(Z<z_1)]\\\\=P(z<2)-(1-P(z<2))\ \ [\because\ P(Z<-z)=1-P(Z<z)]\\\\=2P(z<2)-1\\\\=2(0.9772)- 1 \ \ [\text{By z-table}]\\\\=0.9544](https://img.qammunity.org/2021/formulas/mathematics/high-school/dk8opw5n9tkstmd6ngi16x1u1vu1gt6htj.png)
The number of students scored between a 60 and an 80 = 0.9544 x 200
= 190.88 ≈ 191
Hence , about 191 students scored between a 60 and an 80.