Answer:
0.000025mol/L
Step-by-step explanation:
pH = -log[H3O+]
Here, we know that pH = 4.6 while the concentration of [H30+] is what we are to find. This can be obtained as follows:
4.6 = -log[H30+]
[H3O+] = -Antilog(4.6)
= 0.000025mol/L
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