To solve this problem we will apply the first law of thermodynamics and we will make a balance between the heat transferred, its internal energy and the total work. Recall that for gases the definition of work can be expressed in terms of its pressure and volume. Let's start
![dQ = dU +dW](https://img.qammunity.org/2021/formulas/physics/college/2dycfrm4n3xsud1bmrudr5gaxdn85n2mnh.png)
Here,
dU = Internal Energy
dW = Work
But internal energy is unchanged, then
![dQ = dW](https://img.qammunity.org/2021/formulas/physics/college/x9jbvf5qi0i76er2moxmayv4ekxjpkuoqm.png)
![dQ = PdV](https://img.qammunity.org/2021/formulas/physics/college/21l1tb3bmo9shq34mkgiam3fqgmgv7d9pz.png)
Where
= Change in Volume
P = Pressure
Finally, the expression of the heat transferred can be expressed in terms of pressure and volume, so it would end up becoming
![dQ = p(v_i-v_f)](https://img.qammunity.org/2021/formulas/physics/college/il4llgh0a4veuksmttk3u20hpeieykwief.png)
Replacing,
![dQ = (1500)(0.4-0.25)](https://img.qammunity.org/2021/formulas/physics/college/st6uwfjdpeo3t058uvx60gir8lfho90czk.png)
![dQ = 225J](https://img.qammunity.org/2021/formulas/physics/college/g5s3o36rpuwyavx7gbw35u5avba7l916t3.png)
Therefore the correct answer is B.