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The solutions to a quadratic equation are 6 and 2/3. Which quadratic function is related to this equation?

y = 2² - 15x + 18
y = 3x² + 16x - 12
y = 3x² - 20x + 12
y = 2x² + 9x - 18

User Gaara
by
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1 Answer

5 votes

Answer:

The quadratic equation for the given roots 6 ,
(2)/(3) is y = 3 x² - 20 x + 12

Explanation:

Given as :

The roots of the quadratic equation are 6 ,
(2)/(3)

Let The standard quadratic equation

a x² + b x + c = 0

So, the roots are
\alpha = 6

And
\beta =
(2)/(3)

Sum of roots =
\alpha +\beta

i.e
\alpha +\beta = 6 +
(2)/(3) =
(20)/(3)

The quadratic equation

y = (x - α) (x - β)

Or, y = (x - 6) (x -
(2)/(3))

Or, y = x² -
(2)/(3) x - 6 x + (6 ×
(2)/(3))

Or, y = x² - (
(2)/(3) + 6) x + 4

Or, y = x² - (
(2+18)/(3) ) x + 4

Or, y = x² -
(20)/(3)x + 4

Or, y = 3 x² - 20 x + 12

Hence, The quadratic equation for the given roots 6 ,
(2)/(3) is y = 3 x² - 20 x + 12 . Answer

User Takasu
by
8.0k points