Question

the density of a steel is 7.8.find the mass of steel cube of side 10 cm. find volume of steel if the mass is 8kg​

Answer 1

The mass of a steel cube with a side of 10 cm is 7.8 kg. If a piece of steel has a mass of 8 kg, its volume would be approximately 1025.64 cm³.

Step-by-step explanation:

The density of steel given is 7.8 g/cm³ (which is equivalent to 7800 kg/m³), and to find the mass of a steel cube with side of 10 cm, we first calculate its volume using the formula for volume of a cube V = a³, where 'a' is the length of a side. So, V = 10 cm x 10 cm x 10 cm = 1000 cm³. Next, we can find the mass (m) using the density (p) and volume (V) via the formula m = p x V. The mass is thus 7.8 g/cm³ x 1000 cm³ = 7800 g, or 7.8 kg.

For the second part of the question, if the mass of steel is given as 8 kg, and we want to find the volume, we rearrange the density formula to V = m / p. Using the density in kg/m³, we have V = 8 kg / 7800 kg/m³, which results in a volume of approximately 0.00102564 m³, or 1025.64 cm³.

Answer 2

Mass of the steel cube = 7800 kg

Volume of the steel = 1.025 cubic centimetre

Step-by-step explanation:

Given:

The density of the steel = 7.8

Side of the cube = 12 cm

(1)The mass of steel cube :

We know that,

`Density = (Mass)/(Volume)`

We are given with density and sides of the cube

then volume of the cube

=
`(side)^3`

=
`10^3`

= 1000 cubic centimetre

Now

`7.8 = (mass)/(1000)`

`mass = 7.8 * 1000`

mass = 7800 kg

(2)volume of steel:

Given the mass = 8 kg

`Density = (Mass)/(Volume)`

Substituting the values

`7.8 = (8)/(volume)`

`volume = (8)/(7.8)`

volume = 1.025 cubic centimetre