Question

A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. If the speed of the object when it has moved 50m from O is 500m/s. what is the value of F? ​

Answer 1

F = 100 Newtons

Step-by-step explanation:

F = ?

m = 0.04kg

u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.

s = 50m ==> s is just an abbreviation for distance, it is conventional.

v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

`v^(2) = u^(2) + 2as\\\\=> a = (v^(2) - u^(2))/(2s)\\a = (500^(2) )/(2*50)\\a = 2500ms^(-2)`

Then F = ma = 0.04 x 2500 = 100N