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45 votes
Give the values of a,b, and c after writing the equation in general form.
2/3(x-4)(x+5)=1

User KillerKode
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1 Answer

12 votes
12 votes

Answer:

  • a = 2/3
  • b = 2/3
  • c = -14 1/3 = -43/3

Explanation:

You want the coefficients of the given quadratic equation when it is written in general form.

General form

The general form of a quadratic equation in one variable is ...

ax² +bx +c = 0

We can expand the given equation and subtract the right side constant to give this form.

2/3(x -4)(x +5) = 1

2/3(x² -4x +5x -20) = 1

2/3x² +2/3x -2/3(20) -1 = 0

2/3x² +2/3x -(14 1/3) = 0

The values of a, b, c are ...

  • a = 2/3
  • b = 2/3
  • c = -14 1/3

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Additional comment

It is often convenient for the coefficients to have mutually prime integer values. We can multiply the given coefficients by 3 to achieve that condition:

2x² +2x -43 = 0 . . . . . . a = 2; b = 2; c = -43

The graph of this will have the same x-intercepts as the above equation, but will be stretched vertically by a factor of 3.

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User Wauna
by
3.6k points