Question

Which of the following equations has only one solution?

X^2-8x + 16 = 0
x(x - 1) = 8
x^2 = 16

Answer 1

x^2 - 8x + 16 = 0

Explanation:

Equation 1 :

x^2 - 8x + 16 = 0

x^2 -4x -4x +16 = 0

x (x - 4) -4 (x - 4) = 0

(x - 4)(x- 4)= 0

x= 4

x= 4

x=(4) this Equation have only one solution

Equation 2:

x(x-1)=8

x^2 - x - 8 = 0

After performing quadratic equation on the equation

Answer Comes

x =(3.37 , -2.37)

Equation 3:

x^2 = 16

take square root

sqrt(x^2) = sqrt(16)

x= (+4,-4)

Answer 2

x^2-8x+16=0

(x-4)^2=0

x = 4