Answer:
The speed in of the plane is 115.47 m/sec
Explanation:
Given:
Height at which the plane is flying = 6000 m
Angle of elevation at the radar base = 30 Degrees
Angle of elevation at the radar base after one minute = 60 Degrees
To Find:
The Speed of the plane in meter per second = ?
Solution:
Let us use the tangent of the angle to find the distance (d) to a point directly below plane:
when the angle is 30 degrees
![tan(30) = (6000)/(d1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/r4t3r9r3q20re5oj9h9y7w1x8x7b029zo3.png)
![d1 = (6000)/(tan(30))](https://img.qammunity.org/2021/formulas/mathematics/high-school/3w6vh01rpaaepmnwk4go20gz5mm6dnli26.png)
![d1 = (6000)/(0.577)](https://img.qammunity.org/2021/formulas/mathematics/high-school/apn8yfb4joo291uwkfh2fsmytz8d4aczje.png)
d1 = 10392.3 meters
when the angle is 60 degrees
![tan(60) = (6000)/(d2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/q5uiuo7wkgv9rm2qnvj76mr8d1xx7951gj.png)
![d2 = (6000)/(tan(60))](https://img.qammunity.org/2021/formulas/mathematics/high-school/on1okw5fnrh4bo8qs871ud9byq0773sa2s.png)
![d2 = (6000)/(1.732)\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/lrjjucqgropqytu4ams3ws9mstqj2i7xcn.png)
d2 = 3464.1 meters
distance travelled by aircraft in 1 min is
=>d1 - d2
=>0392.3 - 3464.1
= 6928.2 m/min
Now converting to m/sec
=>
![(6928.2)/(60)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9lzchwrdfv4r20yyptarvbhloupsye40ar.png)
=>115.47 m/sec