Question

Amira is solving the equation x^2 - 6x = 1. Which value must be added to both sides of the equation to make the left side a

perfect-square trinomial?

Answer 1

add 9

Explanation:

x^2 - 6x = 1

now take half of ur x term coefficient and square it

-6 / 2 = -3.....-3^2 = 9

so we add 9 to both sides

x^2 - 6x + 9 = 1 + 9

(x - 3)^2 = 10