Question

What is the entropy change of 450 g of water when it changes from liquid to steam at its usual boiling point? For water,
`L_F` = 0.334 MJ/kg,
`L_V` = 2.26 MJ/kg.

Answer 1

2726.54 J/K

Step-by-step explanation:

Entropy change =
`(m* L_(v))/(T)`

where

m = mass of water = 450g = 0.45kg

`L_(v)` = 2.26 MJ/kg = 2260000 J/kg

T = temperature at which water change from liquid to steam = 100 degree Celsius = 272 + 100 = 373 degree kelvin.

Entropy change =
`(0.4* 2260000)/(373)` = 2726.54 J/K