Answer:
f(4x) = (4x)^2 +2(4x) +3 = 16x^2 +8x +3
f(x-3) = (x-3)^2 +2(x-3) +3 = x^2 -4x +6
Explanation:
Apparently, you want to evaluate ...
for f(x) = x^2 +2x +3.
Put the given argument values in place of the function variable and do the math.
f(4x)
f(4x) = (4x)^2 +2(4x) +3
= 16x^2 +8x +3
__
f(x-3)
f(x-3) = (x-3)^2 +2(x-3) +3
= x^2 -6x +9 +2x -6 +3 = x^2 -4x +6