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Suppose you are fishing and you expect to get a fish once every 30 minutes. Compute the probability that you will have to wait between 2 to 4 hours before you catch 4 fish.

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Answer:

Explanation:

probability that you will have to wait between 2 to 4 hours before you catch 4 fish =P(4 or more fish in 4 hours)-P(4 or more fish in 2 hours) =P(1-at most 3 fish in 4 hours)-P(1-at most 3 fish in 2 hours)


\sum\limits^3 {e^(-8)8^x/x!}\sum\limits^3{e^(-4)4^x/x!}\\\\=(1-x=0)-(1-x=0)\\\\=(1-0.042380)-(1-0.433470)=0.391090

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