Question

If , x - 12 square root of x + 36 = 0what is the value of x? A. 6 B. 6^2 C. 6^3 D. 6^4

Answer 1

Option B)
`6^2` is correct.

That is in the given equation
`x-12√(x)+36=0` the value of x is
`6^2`

ie.,
`x=6^2`

Explanation:

The given equation is
`x-12√(x)+36=0`

To find the value of x in the given equation :

`x-12√(x)+36=0`

Rewritting the above equation as below :

`√(x)^2-2(√(x))(6)+6^2=0`

Which is in the form of
`(a-b)^2=a^2-2ab+b^2`

Here
`a=√(x)` and b=6

Therefore it can be written as

`(√(x)-6)^2=0`

`√(x)-6=0`

`√(x)=6`

Squaring on both sides we get

`(√(x))^2=6^2`

`x=6^2`

Therefore in the given equation
`x-12√(x)+36=0` the value of x is
`6^2`

Therefore Option B)
`6^2` is correct.