Question

PLEASEE HELPP!!!
What is the mistake in setting up the quadratic formula?

Answer 1

First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) . See examples of using the formula to solve a variety of equations.

Answer 2

That 6 should be -6

Let me solve it for you

`\\ \rm\rightarrowtail 2x-x-6=0`

So

`\\ \rm\rightarrowtail x=(-b\pm √(b^2-4ac))/(2a)`

`\\ \rm\rightarrowtail x=(-(-1)\pm√((-1)^2-4(2)(-6)))/(2(2))`

`\\ \rm\rightarrowtail x=(1\pm √(1+48))/(4)`

`\\ \rm\rightarrowtail x=(1\pm 7)/(4)`

`\\ \rm\rightarrowtail x=(8)/(4)\:or\:(-6)/(4)`

`\\ \rm\rightarrowtail x=2\:or\:(-3)/(2)`