Question

Hydrogen and nitrogen react to form ammonia according to the reaction, 3 H2 + N2 â> 2 NH3. If 4.0 moles of H2 with 2.0 moles of N2 are reacted, how many moles of NH3 would be produced?

a) 1 mol
b) 2 mol
c) 4 mol
d) 2.7 mol

Answer 1

d) 2.7 mol

Step-by-step explanation:

• 3 H2 + N2 → 2 NH3

limit reagent is H2:

∴ Mw H2 = 2.016 g/mol

∴ Mw N2 = 28.0134 g/mol

⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)

⇒ moles NH3 = 2.666 mol

⇒ moles NH3 ≅ 2.7 mol