1 Answer

Michael Gallego · Answer 1 · 2021-06-15T01:54:34+0000

Answer:

The products of AB and BA is given by

AB=
$\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA=
$\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

Explanation:

Given the matrices A=
$\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]$ and

B=
$\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]$

To find the product AB and BA

AB=
$\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]$

$=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]$

Therefore the product of AB is

AB=
$\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA=
$\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]$
$\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]$

$=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]$

Therefore the product of BA is

BA=
$\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

The products of AB and BA is given by

AB=
$\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA=
$\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

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