Question

A 0.200 kg plastic ball moves with a velocity of 0.30 m/s. It collides with a second plastic ball of mass 0.100 kg, which is moving along the same line at a speed of 0.10 m/s. After the collision, both balls continue moving in the same, original direction, and the speed of the 0.100 kg ball is 0.26 m/s. What is the new velocity of the first ball?

Answer 1

To find the new velocity of the first ball after the collision, we can use the principle of conservation of momentum. By setting up an equation with the initial velocities and the masses of the two balls, we can solve for the new velocity. The new velocity of the first ball is 0.233 m/s.

Step-by-step explanation:

To solve this problem, we can use the principle of conservation of momentum. Before the collision, the total momentum of the system is the sum of the individual momenta of the two balls. After the collision, the total momentum of the system is still the same.

Let's denote the velocity of the 0.200 kg ball before the collision as v1, and the velocity of the 0.100 kg ball before the collision as v2. According to the problem, v1 = 0.30 m/s and v2 = 0.10 m/s.

To find the new velocity of the 0.200 kg ball after the collision, we can set up the equation:

(0.200 kg)(v1) + (0.100 kg)(v2) = (0.200 kg + 0.100 kg)(new velocity)

Substituting the given values, we have:

(0.200 kg)(0.30 m/s) + (0.100 kg)(0.10 m/s) = (0.300 kg)(new velocity)

Simplifying the equation, we get:

0.060 kg m/s + 0.010 kg m/s = 0.300 kg(new velocity)

0.070 kg m/s = 0.300 kg(new velocity)

Solving for the new velocity, we have:

new velocity = 0.070 kg m/s / 0.300 kg = 0.233 m/s

Therefore, the new velocity of the first ball is 0.233 m/s.

Answer 2

0.22m/s

Step-by-step explanation:

The total momentum of the System is conserved. Total momentum of the system before the collision is equal to the total momentum of the system after collision. The total momentum is the sum of individual momentum of all the objects in that system.

momentum of an object = mass* velocity

Total Momentum before collision = 0.2*0.3 + 0.1*0.1= 0.07 kg⋅m/s;

Total momentum after collision = 0.1*0.26 + 0.2*x = 0.07;

Solve for x.