Five sales men could sell 18 cars
Solution:
The number of cars sold is proportional to the number of salesmen
![\text{Number of cars sold } \propto \text{Number of salesmen }](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xyyxvyz1t5pf5mj42jjtoael47hk8irwqv.png)
Let "c" be the number of cars sold
Let "s" be the number of salesmen
Then we get,
![c \propto s](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x1m6al8in2grz85bol3ofqrrku0xnablkg.png)
c = ks -------- eqn 1
Where "k" is the constant of proportionality
Three salesmen sold eleven cars
Therefore, substitute s = 3 and c = 11 in eqn 1
![11 = k * 3\\\\k = (11)/(3) = 3.67](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lzo7zbod6ef2jp0kyyesj31ms6r6xfp3xt.png)
How many could five salesmen have sold ?
Therefore, s = 5 and c = ?
Substitute s = 5 and k = 3.67 in eqn 1
![c = 3.67 * 5\\\\c = 18.35 \approx 18](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1bj6hgucd9l3hhawcnhken16h6e9ayv01u.png)
Thus five men sold 18 cars