Answer:
C) 5.5
Explanation:
The expected value is the sum of products of points and the probability of obtaining those points.
The probabilities are ...
P(HH) = 1/4
P(HT or TH) = 1/4 +1/4 = 1/2
P(TT) = 1/4
Then the expected value of the score is the sum of ...
10×P(HH) = 10/4 = 2.5
8×P(TT) = 8/4 = 2.0
2×P(HT or TH) = 2/2 = 1.0
The expected score is 2.5+2.0+1.0 = 5.5.