Check the picture below.
so, if we get the whole area of the figure, which will be the combined areas of those three rectangles, and if we get the area of the triangle, and then subtract that area from of the triangle from the whole figure's area, we're in effect making a whole in the total area, and what's leftover is the shaded area.
![\bf \stackrel{\textit{area of the rectangles}}{(1.6\cdot 5.2)+(2.7\cdot 8.4)+(1.6\cdot 5.2)}~~-~~\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(2.7)(8.4)} \\\\\\ 8.32+22.68+8.32~~-~~11.34\implies 39.32-11.34\implies 27.98](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rznhrh9h1h4awyk64vvq1fs0d8l6xs3eug.png)