Question

Click on the element in the periodic table to explore the atomic radii of elements from Period 3 and Group 17. Fill in the missing values in the table so you can compare the atomic radii of the elements. After the table is filled in, compare the values in each column.

A =

B =

C =

No one answered.
Answer is
A: 1.12
B 1.6
C: 1.9

Answer 1

A: 1.12

B 1.6

C: 1.9

Step-by-step explanation:

Answer 2

These are experimentally reported values , The values are

A = Bromine = 1.12 Angstrom

B = Magnesium = 1.6

C = Sodium = 1.9

Order of Atomic radius :

Sodium > Magnesium >Phosphorus > Bromine > Chlorine

Step-by-step explanation:

In order to explain the answer , look some basic concepts of the periodic table:

The periodic table is the arrangement of element in increasing order of their atomic number.

Modern periodic table is divided into two parts :

1. Periods : The horizontal rows are called the periods. There are seven periods in the periodic table.The period of the element tells about the electron shell.

For example the element of period 2 = contain 2 shell( from Li to Neon)

Along the period the atomic size decreases. This is because the effective nuclear charge increases along the period

2. Groups : The vertical columns are called the groups . The group number of the element tell about the number of electron in outermost shell.

For example the element of group 3 = has 3 electrons in their outermost shell(Boron , Aluminium , Gallium , Indium , Thallium)

Down the group the atomic size increases because each the number of shells increases on going down.

For example example :

Boron = 2 shells

Al = 3 shell , In = 4 shells

The given table is :

Bromine = 1.12

Chlorine = 0.97

Magnesium = 1.6

Sodium = 1.9

Phosphorus = 1.28

Order of size :

Sodium > Magnesium >Phosphorus > Bromine > Chlorine

How to proceed :

1. First , find out their atomic number

Bromine = 35

Chlorine = 17

Magnesium = 12

Sodium = 11

Phosphorus = 15

2.Find the electronic configuration :

Bromine = [Ar] 3d10 4s2 4p5

Chlorine = [Ne] 3s2 3p5

Magnesium = [Ne] 3s2

Sodium = [Ne] 3s1

Phosphorus = [Ne] 3s2 3p3

3. Check the elements which belong to halogen family : They have smallest atomic radii. Here, Bromine and chlorine .

These have smallest size because of more effective nuclear charge.

.(These elements are present on Right side of the periodic table)

But Bromine = 4 shell and chlorine =3 shell

So Cl = smallest radii

Hence,radii Bromine > Chlorine

4 .Check the elements which belong to "Alkali "family : They have largest atomic radii. Here sodium.(These elements are present on extreme left side of the periodic table)

So Size , of sodium = maximum

Then search the alkaline metal ion : These are large in size , also present on left side of periodic table

Hence

Magnesium is second large atom

So trend is :

Sodium > Magnesium >Phosphorus > Bromine > Chlorine