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Seven more than the quotient of a number b and 45 is greater than 5.

User Fralle
by
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1 Answer

5 votes

Answer/Step-by-step explanation:

Given:

Seven more than the quotient of a number b and 45 is greater than 5

So:

Seven more than the quotient of a number b and 45 is greater than 5

=

7 + b/45 > 5

Solve if needed:


\begin{bmatrix}\mathrm{Solution:}\:&\:b > -90\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-90,\:\infty \:\right)\end{bmatrix}


\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}


7+(b)/(45)-7 > 5-7


\mathrm{Simplify}


(b)/(45) > -2


\mathrm{Multiply\:both\:sides\:by\:}45


(45b)/(45) > 45\left(-2\right)


\mathrm{Simplify}


b > -90

~Lenvy~

User Vinoy Alexander
by
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