Question

LAST QUESTION OF MY HOMEWORK AND IM CONFUSED, CAN SOMEONE PLEASE HELP! :)

Answer 1

Therefore the equation of the line through ( -10 , -3 ) and ( -5 , -1 ) is

`2x-5y=-5`

Step-by-step explanation:

Given:

We Know that to have an equation of a line which required two points so from the table we will consider two points say,

Let,

point A( x₁ , y₁) ≡ ( -10 ,-3)

point B( x₂ , y₂) ≡ (-5 , -1)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

`(y - y_(1) )=((y_(2)-y_(1) )/(x_(2)-x_(1) ))* (x-x_(1)) \\`

Substituting the given values in a above equation we get

`(y - (-3) )=((-1-(-3) )/(-5-(-10)))* (x-(-10)) \\`

`(y +3 )=((-1+3) )/(-5+10) })* (x+10) \\`

`(y +3 )=((2)/(5))* (x+10) \\5y+15=2x+20\\2x-5y=-5` is the required Equation of line.

Therefore the Equation of Line is

`2x-5y=-5`