Answer:
5 generations
Explanation:
Data provided in the question:
Number of bacteria at the beginning of a time interval , B = 4
Number of bacteria at the end of the time interval, b = 128
Now,
The relation between the bacteria at the beginning, bacteria at the end and the number of generations (n) is given as:
b = B × 2ⁿ
Therefore,
on substituting the respective values, we get
128 = 4 × 2ⁿ
or
2ⁿ = 32
or
2ⁿ = 2⁵
or
n = 5
hence,
5 generations