Answer:
There are 72 dimes having a total value of $7.2.
Explanation:
Let the number of dimes be 'd', nickels be 'n' and quarters be 'q'.
Given:
Number of dimes is three times quarters
Number of nickels is four less than twice the number of dimes.
Total amount in the piggy bank is $20.20
Now, as per question:
Number of dimes is three times quarters
Framing in equation form, we get:
![d=3* q\\d=3q\\q=(d)/(3)---1](https://img.qammunity.org/2021/formulas/mathematics/high-school/egcgat3rca2qaacxdqlxpemqjujmm6gozd.png)
Number of nickels is four less than twice the number of dimes.
Framing in equation form, we get:
![n=2d-4----2](https://img.qammunity.org/2021/formulas/mathematics/high-school/60nnf2yyxrvt1v62j80xjri6wj3bny4vxb.png)
Now, value of 1 dime in dollars is 0.1.
Value 'd' dimes = $0.1d ----------(A)
Value of 1 quarter = $0.25
Value of 'q' quarters = $0.25q ----------(B)
Value of 1 nickel = $0.05
Value of 'n' nickels = $0.05n ----------(C)
Now, total amount is equal to the sum of all the amounts of each type of coin.
So, adding equations (A), (B) and (C) and equating to 20.20, we get:
![0.1d+0.25q+0.05n=20.20](https://img.qammunity.org/2021/formulas/mathematics/high-school/tzrccf1mlnaovpjwdcqmavxy2ge6cnqxdo.png)
Now, using equations (1) and (2), the above equation can be rewritten as:
![0.1d+0.25((d)/(3))+0.05(2d-4)=20.20\\\\0.1d+(d)/(12)+0.1d-0.2=20.20\\\\d(0.1+0.1+(1)/(12))=20.20+0.2\\\\0.2833d=20.40\\\\d=(20.40)/(0.2833)=72](https://img.qammunity.org/2021/formulas/mathematics/high-school/7ppyhjn71qmf83df4z74ym0o22sy3gtzty.png)
So, there are 72 dimes in the piggy bank.
Total value of 72 dimes = 72(0.1) = $7.2