Question

To see why, calculate the energy absorbed from your body if you eat 0.70 kg of -9 ∘c snow which your body warms to body temperature of 37∘c.

Answer 1

The energy absorbed from the body = 302.82 J

Step-by-step explanation:

Note: a Snow is an an ice

The heat absorbed from the body = heat required to change the temperature of snow from -9 °C to 37 °C. + The latent heat of snow

H = c₁m(t₂-t₁) + c₂m ........................... Equation 2

Where H = heat absorbed from the body, c₁ = specific heat capacity of ice, c₂ = specific latent heat of fusion of ice, m = mass of ice.

Given: m = 0.7 kg, t₂ = 37 °C, t₁ = -9 °C

Constant: c₁ = 2.1 g/g.°C, c₂ = 336 J/g

Substituting these values into equation 1,

H = 0.7×2.1×(37+9) + 0.7(336)

H = 67.62 + 235.2

H = 302.82 J

Thus, the energy absorbed from the body = 302.82 J