Answer:
Explanation:
0.226 gram.
Explanation:
You can get to the answer in two steps:
calculate:
3.40
⋅
10
22
atoms =
x
mol ?
using Avogadro's constant.
calculate:
x
mol =
?
grams,
using the atomic mass of Helium.
Step 1
Avogadro's constant says that
1
mole of any atom contains
6.022
⋅
10
23
atoms. In this case you have
3.40
⋅
10
22
atoms:
3.40
⋅
10
22
atoms
6.022
⋅
10
23
atoms
mol
=
5.65
⋅
10
−
2
m
o
l
Step 2
The atomic mass of helium (He) will give you the weight of one mole of this molecule:
1
mol =
4.00
gram:
4.00
g
mol
⋅
5.65
⋅
10
−
2
mol
=
0.226
g
So the
3.40
⋅
10
22
helium atoms weigh
0.226
gram
I HOPE THIS HELP