Question

How many solutions does this linear system have?

y= 2x-5
-8x – 4y = -20
O one solution: (-2.5, 0)
O one solution: (2.5, 0)
O no solution
O infinite number of solutions

Answer 1

One solution: (2.5,0)

Explanation:

We can use substitution for the solution. Substitute y=2x-5 to -8x-4y=-20 so that you end up with -8x-8x+20=-20. Next you want to add like terms which will be -16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with -16x=-40. Divide -16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2(2.5)-5 which will then lead to y=0.