Question

3x-8y=-50 6y=x solve by substitution​

Answer 1

To solve the system of equations 3x-8y=-50 and 6y=x by substitution, you need to solve one equation for one variable and substitute it into the other equation.

Step-by-step explanation:

To solve the system of equations 3x-8y=-50 and 6y=x by substitution, you need to solve one equation for one variable and substitute it into the other equation. Let's solve the second equation 6y=x for y first:

6y=x => y = x/6

Now, substitute this value of y into the first equation:

3x-8(y)=-50
3x-8(x/6)=-50
Simplify:
3x-(8/6)x=-50
3x-(4/3)x=-50
(9/3)x-(4/3)x=-50
(5/3)x=-50
Multiply both sides by 3/5:
x = -30

Now, substitute this value of x back into the second equation:
y = x/6 = -30/6 = -5

Answer 2

Step-by-step explanation:

3x-8y=-50.........(1)

6y= x ..............(2)

Substituting x = 6y in (1)

3(6y) - 8y = -50

18y - 8y = -50

10y = -50

y = -50/10

y = -5

Putting y = -5 in (2)

6y = x

6(-5) = x

-30 = x

x = -30