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The length of a line segment is 13 units. One end point of the line segment is -3,7. Find four points that could be the other end points of the line segment

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Answer:

The points are (-16,7),(10,7),(-3,-6) and (-3,20)

Explanation:

We have that one endpoint is at (-3,7) and the length is 13 units.

A point that is 13 units horizontally to the left and right will have the same y-coordinate but with x-coordinates that are 13 units from -3.


| - 3 - x| = 13


( - 3 - x) = 13 \: or \: - ( - 3 - x) = 13


x = - 16 \: or \: x = 10

Hence we have (-16,7) and (10,7)

Also a point that is 13 units vertically up and down will have the same x-coordinate but with y-coordinates that are 13 units from 7.


|y - 7| = 13


(y - 7) = 13 \: or \: - (y - 7) = 13


y= - 6 \: or \: y = 20

Hence we again have (-3,-6) and (-3,20)

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