Answer:
True
Explanation:
This is true for a>0 and x>0. We can prove it by plugging in a and x for f(x) = ln(x)
f(ax) = ln(ax) = ln(a) + ln(x)
We see that ln(a) + ln(x) is exactly f(a) + f(x)
Therefore, the statement above is true for any a>0 and x>0